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In the past, a precise measurement of a magnetic field this was often accomplish

ID: 1434591 • Letter: I

Question

In the past, a precise measurement of a magnetic field this was often accomplished with a flip coil . A coil of wire was

oriented in a plane perpendicular to magnetic field; it was then quickly turned to be parallel to the field. The resulting

flux change induced a current who measurement permitted a determination of the field.

An investigator measures the strength of the field in a large magnet with a flip coil of radius 12 cm and resistance 0.30

. The coil is rotated as noted in a time of 0.15 s. If the magnitude of the current is 0.25 A, what is the magnitude of the

field? Be sure to explain your reasoning and show all steps in your work.

Explanation / Answer

Induced emf e = A*dB/dt = pi*r^2*B/t = 3.142*0.12^2*B/0.15 = i*R = 0.25*0.3


magnetic field is B= (0.25*0.3*0.15)/(3.142*0.12^2)

B =0.248 T

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