During a neighborhood baseball game in a vacant lot, a particularly wild hit sen

Question

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.142-kg baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 15.9 m / s, shatters the glass as it passes through, and leaves the window at 12.1 m / s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball?

Calculate the magnitude of this impulse (a positive number).

The ball is in contact with the glass for 0.0103 s as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number).

Explanation / Answer

(1)We know that the impulse is equal to change in momentum therefore the impulse direction will be opposite to
that of the ball direction.
(2) Magnitude of impulse = (0.142) (15.9 - 12.1) = 0.5396 kg -m/s
(3) We know that
force*time = impulse
force = impulse/time = .5396/0.0103 = 52.388 N

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