A 650-g block is dropped onto a relaxed vertical spring that has a spring consta
ID: 1433278 • Letter: A
Question
A 650-g block is dropped onto a relaxed vertical spring that has a spring constant k =200.0 N/m. The block becomes attached to the spring and compresses the spring 70.5 cm before momentarily stopping. While the spring is being compressed
A 650-g block is dropped onto a relaxed vertical spring that has a spring constant k-200.0 N/m. The block becomes attached to the spring and compresses the spring 70.5 cm before momentarily stopping. While the spring is being compressed block by the aravitational force on it? what work is done on the Submit Answer Tries 0/6 While the spring is being compressed, what work is done on the block by the spring force? Submit Answer Tries 0/6 What is the speed of the block just before it hits the spring? (Assume that friction is negligible.) Submit Answer Tries 0/6 If the speed at impact is doubled, what is the maximum compression of the spring? Submit Answer Tries 0/6 Threadediew C NEW Anonymous 1 Reply (Tue Mar 8 09:06:48 pm 2016 (CST)) Chronological View ther Views eneral preferenc what ark Export nger neExplanation / Answer
Here
mass of block , m = 0.65 Kg
k = 200 N/m
x = 70.5 cm = 0.705 m
work done by gravitational force = m * g * x
work done by gravitational force = 0.65 * 9.8 * 0.705 J
work done by gravitational force = 4.49 J
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work done by the spring force = - 0.5 * k * x^2
work done by the spring force = - 0.5 * 200 * 0.705^2
work done by the spring force = -49.7 J
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let the speed of the block is v
Using conservation of energy
0.5 * 0.65 * v^2 = - 4.49 + 49.7
v = 11.8 m/s
the speed of the block just before it hits the spring is 11.8 m/s
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let the compression is x
for double the speed
0.5 * 200 * x^2 - m * g * x = 0.5 * 0.65 * (2 * 11.8)^2
0.5 * 200 * x^2 - 0.65 * 9.8 * x = 0.5 * 0.65 * (2 * 11.8)^2
solving for x
x = 1.314 m
the spring compression is 1.314 m
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