By accident, a large plate is dropped and breaks into three pieces. The pieces f
ID: 1433246 • Letter: B
Question
By accident, a large plate is dropped and breaks into three pieces. The pieces fly apart parallel to the floor, with v1 = 3.10 m/s and v2 = 2.00m/s. As the plate falls, its momentum has only a vertical component, and no component parallel to the floor. After the collision, the component of the total momentum parallel to the floor must remain zero, since the net external force acting on the plate has no component parallel to the floor. Using the data shown in the drawing, find the masses of pieces 1 and 2.
m1 = kg m2 = kgExplanation / Answer
along the X-direction :
final momentum = initial momentum
- m1(V1 Sin25) + m2 V2 Cos45 = 0
m1 (3.1) Sin25) = m2 (2)Cos45
m1 = 1.08 m2 eq-1
along the Y-direction :
final momentum = initial momentum
m1 V1 Cos25 + m2 V2 Sin45 - m3 V3 = 0
m1 (3.10) Cos25 + m2 (2) Sin45 - (1.3) (3.07) = 0
using eq-1
m1 (3.10) Cos25 + m2 (2) Sin45 - (1.3) (3.07) = 0
(1.08 m2 ) (3.10) Cos25 + m2 (2) Sin45 - (1.3) (3.07) = 0
m2 = 0.897 kg
using eq-1
m1 = 1.08 m2 = 1.08 x 0.897 = 0.97 kg
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