Do not give 1.00 m/s in the opposite direction as your answer it is wrong. pleas

Question

Do not give 1.00 m/s in the opposite direction as your answer it is wrong. please show your work.

Thank you

A 2.00 kg block with a speed of 3.00 m/s collides with a 10.0 kg block that has a speed of 1.00 m/s in the same direction. After the collision, the 10.0 kg block is observed to be traveling in the original direction with a speed of 1.80 m/s. What is the velocity (speed and direction) of the 2.00 kg block immediately after the collision?

{Assume no friction, as the law of conservation of linear momentum can only be applied if all external forces on the isolated system are 0.}

1.20 m/s in the opposite direction

1.00 m/s in the opposite direction

2.42 m/s in the same direction

0.580 m/s in the same direction

Do not give 1.00 m/s in the opposite direction as your answer it is wrong. please show your work.

Thank you

1.20 m/s in the opposite direction

1.00 m/s in the opposite direction

2.42 m/s in the same direction

0.580 m/s in the same direction

Do not give 1.00 m/s in the opposite direction as your answer it is wrong. please show your work.

Thank you

Explanation / Answer

let the speed be v
conservation of momentum
conservation of momentum:

MV+mv=MV' + mv'

5 * 3 + 10*1 = 10 * 1.8 + 2* v

2v = 7

v=3.5m/s

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