Step 1 The drift speed of charge carriers in a conductor carrying current I is v

Question

Step 1

The drift speed of charge carriers in a conductor carrying current I isvd =

A = r2 = (1.0 102 m)2 = 104 m2.

In metallic conductors, the mobile charge carriers are electrons, each with a charge of magnitude q = e. We are given the density n of free electrons in this copper material per unit volume. Thus, the drift speed of the electrons?

Step 2

The time t that the electrons require to drift the length L of the cable ?

asking for vd and delta t; I cant get the right numbers plugged in

so show me what you do in details pls

Explanation / Answer

Given :-

I = 1045 Amp = 1045 C/sec

A = 104 m2.

q = 1.6 x 10^-19 C

n = 8.5 x 10^28 C/m^3

Vd = I / nqA

Vd = 1045 / (8.5 x 10^28 x 1.6 x 10^-19 x   104)

Vd = 2.4470 x 10^-4 m/s.

time = (245 x 10^3) / (2.4470 x 10^-4)

time = 100.1225991 x 10^7 sec

time = 31.848667 years

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