Problem 23.5 The lightbulb in the circuit diagram of has a resistance of 1.1 ·Co

Question

Problem 23.5 The lightbulb in the circuit diagram of has a resistance of 1.1 ·Consider the potential difference between pairs of points in the figure. Suppose that -4.0 v 2.0 Part A What is the magnitude of ? Express your answer with the appropriate units AVValue Units Submit Incorrect; Try Again; 4 attempts remaining My Answers Give Up Part B What is the magnitude of Express your answer with the appropriate units %-| Value |v Submit Incorrect; Try Again; 5 attempts remaining My Answers Give Up Part C

Explanation / Answer

here,
resistance of bulb, r = 1.1 ohms

As the R, r in series therefore
Req = (2 + 1.1)
Req = 3.1 ohms

From ohm's Law,
V = current * Equivalent resistance
V = I * R

net curernt, I
In = V /Req
In = 4 /3.1
In = 1.29 A

Part A :
V1- V2 is the potential drop by the resistance. R = 2 ohms
V12 = In*R
V12 = 1.29 * 2
V12 = 2.58 V

Part B :
From Ohms' law
V = In*r
V = 1.029 * 1.1
V = 1.132 V

Part C:
if the bulb is removed, then V will remain same as there is no power consuming device.
V = 4 V

Part D:
if the bulb is removed, then V will remain same as there is no power consuming device.
V = 4V

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.