The relativistic momentum p and energy E of a particle with mass m moving with v

Question

The relativistic momentum p  and energy E of a particle with mass m moving with velocity v  are given by

p =mv 1v2c2

and

E=mc21v2c2.

Part A

Find the momentum p, in the laboratory frame of reference, of a proton moving with a speed of 0.724 c . Use 938MeV/c2 for the mass of a proton. Express your answer in MeV/c to three significant figures.

Part B

Find the total energy E of this proton in the laboratory frame.

Express your answer in millions of electron volts to three significant figures.

Part D

What is the rest mass m of a particle traveling with the speed of light in the laboratory frame.

Express your answer in MeV/c2 to one decimal place.

Explanation / Answer

given that

PART A

speed of proton V =0.724 c

mass of proton M =938 Mev /c2

the momentum P =mv

=938*0.724 =679.112 MeV/c

PART :B

total energy = MC^2

=(938)*(931.5) =873.747 MeV

PART:D

MASS =939.573 MeV/c^2

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