Scientists want to place a 3900 kg satellite in orbit around Mars. They plan to

Question

Scientists want to place a 3900 kg satellite in orbit around Mars. They plan to have the satellite orbit a distance equal to 2.2 times the radius of Mars above the surface of the planet. Here is some information that will help solve this problem:

mmars = 6.4191 x 1023 kg

rmars = 3.397 x 106 m

G = 6.67428 x 10-11 N-m2/kg2

1) What is the force of attraction between Mars and the satellite?

2) What speed should the satellite have to be in a perfectly circular orbit?

3) How much time does it take the satellite to complete one revolution?

4) Which of the following quantities would change the speed the satellite needs to orbit at? the mass of the satellite? the mass of the planet? the radius of the orbit?

5) What should the radius of the orbit be (measured from the center of Mars), if we want the satellite to take 8 times longer to complete one full revolution of its orbit?

if you have these answers and post them I will not rate you

1)2991

2)2394

3)19610

if you answer the qestions right I will rate you 5 stars

Explanation / Answer

(a)

F = G Mmars m/ R^2

here R = R mars + 2.2 R mars = 3.2 R mars

F = 6.67 * 10 ^-11 ( 6.4191 * 10 ^23 kg)( 3900)/(3.2 * 3.397 * 10^6 m)^2

=1413.10 N

(b)

v = sqrt G M mars/ R mars

= sqrt 6.67 * 10^-11 (( 6.4191 * 10 ^23 kg)/(3.2 * 3.397 * 10^6 m)

=1984.6m/s

(c)

T = 2 pi R/ v

= 2 pi ((3.2 ( 3.397 * 10^6 m)/1984.6 m/s

=34415.36 s ( h/ 3600 s) = 9.55 h

4)

speed of the satellite depends on the mass of the planet and radius of the orbit.

as per chegg guidelines i did 1st 4 parts

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