08.4 A large box 5.0 m on a side has mass 100 kg. A force F is applied as shown,
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Question
08.4 A large box 5.0 m on a side has mass 100 kg. A force F is applied as shown, making an angle ? = 30o with respect to the vertical. The coefficient of static friction between the box and the floor is 0.30. What range of values for the force F will tip the box over without having the box slide?
08.4 A large box 5.0 m on a side has mass 100 kg. A force F is applied as shown, making an angle = 300 with respect to the vertical. The coefficient of static friction between the box and the floor is 0.30. What range of values for the force F will tip the box over without having the box slide?Explanation / Answer
Normal force,N=mg cos (theta)=100*9.8*cos30=848.70 N
The static friction force,Fs needed such that the block will move is, Fs=coeffecient friction*N
Fs=0.3*848.70=254.61 N
So an applied force of 255 N makes the box moves
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