Date: Name: 74 LAB 3 | Inheritance SCENARIO B or in a small group to complete th

Question

Date: Name: 74 LAB 3 | Inheritance SCENARIO B or in a small group to complete the dihybrid cross and questions that follow. Consider two traits in humans: freckles (F1 and widow's peak (Wi. Having freckles (F) is dominant over not having freckles ( and having a widow's peak (W) is dominant over not having a widow's peak (wl. Suzy is heterozygous for freckles and widow's peak Jose is homozygous recessive for freckles and widow's peak. Suzy and Jose are about to have a baby, and they are curious about the likelihood that the child will inherit these traits STEP1 Enter Suzy's and Jose's genotypes in the Punnett square. STEP 2 Enter Suzy's and lose's possible gametes in the shaded rows and columns STEP 3 Complete the Punnett square and answer the following questions Suzy's genotype 1. What is the likelihood that Suzy and lose's child will have freckles but will not have a widow's peak? 2. What is the likelihood that Suzy and lose's child will not have freckles but will have a widow's peak? 3. What is the likelihood that Suzy and Jose's child will have freckles and a widow's peak? 4. What is the likelihood that Suzy and lose's child will not have freckles or a widow's peak

Explanation / Answer

A cross in between 2 organisms in which two phenotypic traits are taken is considered as dihybrid cross. Suzy is heterozygous for both the freckles and the widows peak while Jose is homozygous recessive for both the freckles and the widows peak.

If the alleles, 'F' is dominant and 'f' is recessive for the freckles; 'W' is the dominant and 'w' is recessive for the widows peak. Then, the genotype of the Suzy would be 'FfWw' and the genotype of the Jose would be 'ffww'.

Suzy will produce 4 different types of gametes, that is FW, Fw, fW, and fw while Jose will produce only one type of gamete which is fw.

The mating in between the Suzy and Jose can lead to these possibilities.

FfWw

(Freckles, widows peak)

Ffww

(Freckles)

ffWw

(Widows peak)

ffww

(-)

The probability of the occurence of the phenotype can be calculated by using the formula n/total number of offspring, where n is the number of the desired phenotype in the progeny.

Answer 1. The probability of having a child having freckles only and no widows peak is 1/4.

Answer 2. The probability of having a child having widows peak only and no freckles is 1/4.

Answer 3. The probability of having a child having freckles and widows peak both is 1/4.

Answer 4. The probability of having a child having no freckles and no widows peak is 1/4.

Gametes FW Fw fW fw fw

FfWw

(Freckles, widows peak)

Ffww

(Freckles)

ffWw

(Widows peak)

ffww

(-)

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