https://session masteringph hys201-2016-Spring haplerB Problem 8.65 m/myct/itemV
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https://session masteringph hys201-2016-Spring haplerB Problem 8.65 m/myct/itemView?assignmentProblemID-56099951 e previous 18 of 18 retun to assign Problem 8.65 Part A What is the diameter of the airplane's path around the alrport? Express your answer to two significant figures and include the appropriate units. Y ou are flying to New York Youve been reading the in-fight magazine, which has an article about the physics of flying You leamed that the airflow over the wings creates a lift force that is always perpendicular to the wings In level flight, the upward ift force exactly balances the downward eight force The pilat comes on to say that, because of heavy traffic, the plane is going to circle the airport for a while. She says that you maintain a speed of 300 mph at an altitude of 20,000 ft You start to wonder what the diameter of the plane's circle around the airport is. You notice that the pilot has banked the plane so that the wings are 10 from horizontal. The safety card in the seatback pocket infoems you that the plane's wing span is 250 ft Value Units Submit My Answers Ge UpExplanation / Answer
8.62:
using circular motion (a_c = v^2 / L ) and Newton's second law (Fnet = ma )
T = m a_c
T = m v^2 / L
T can be maximum 40 N .
according to that tension, lets find the maximum velocity.
40 = 0.400 v^2 / 1.2
v = 10.95 m/s
when speed of block reaches 10.95 m/s, string will break.
Normal raection of block. N = mg
frictional force , f = uN = 0.60mg = 0.60 x 0.40 x9.8 = 2.35 N
tangential force, Fnet = Fth - f = m a_t
4.91 - 2.35 = 0.4 a_t
a_t = 6.40 m/s^2
this is tangential acceleration which increases speed of block.
Using vf^2 - vi^2 = 2 a d
10.95^2 - 0^2 = 2(6.40 )(d)
d =9.37 m
revolutions = d / 2pi r =9.37 / ( 2 pi 1.2) = 1.24 revolutions
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