Please show all work and make sure that the work can be easily to read and under
ID: 1429736 • Letter: P
Question
Please show all work and make sure that the work can be easily to read and understand. Thank you very much.mass mg is standing on a plank of mass Both are originally at rest on frictionless, flat surface. The girl begins to walk along o the right relative to the plank. (The subscript 1. A gir l of mass mg is standing on a frozen lake that constitutes a fric the plank at a constant velocity vgp to the right relative to the p gp denotes the girl relative to plank. (a) What is the magnitude of the velocity pi of the plank relative to the surface of e magnitude of the velocity tpl of the plank relative to the surface of the ice? [4 pts] (b) What is the magnitude of the girl's velocity vgi relative to the ice surface? [4 ptas (c) If the girl walks a distance r along the plank and then stops, how far does the plank move relative to the surface of the ice? (3 pts] (d) How far does the center-of-mass of the girl-plank system move relative to the ice? [2 pts
Explanation / Answer
a) suppose plank moves with velocity Vp in relative to ice surface in opposite direction.
Vgp = velocity of girl relative to surface - Vp
Vg = Vgp + Vp
intially momentum of plank-girl system was zero.
using momentum conservation,
0 = mg ( Vgp + Vp) - mpVp
Vp ( mp - mg ) = mg Vgp
Vp = mg Vgp / (mp - mg)
b) Vgp =Vg - Vp
Vg = Vgp + Vp = Vgp + mg Vgp / (mp - mg)
Vg = (mp Vgp - mg Vgp + mg Vgp) / (mp - mg )
Vg = mp Vgp / (mp - mg)
c) position of centre of mass plank-girl system will not change.
suppose plank moves distance d in opposite direction.
0 = mg (x - d) + (mp)(- d)
mgx = (mg + mp)d
d = mg x / (mg + md)
d) centre of mass of system doesn't move.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.