1, The dia gram shows two points in an electric field: point 1 is at (x1 , y1 )

Question

1, The diagram shows two points in an electric field: point 1 is at (x1 ,y1 ) = (7, 4), and point 2 is at (x2 , y2 ) = (12, 9),in metres.

The electric field is constant, with a magnitude of 56V/ m, and is directed parallel to the +x axis. The potential at point 1 is 1200V. Calculate the potential at point 2. Hint: To calculate the potential between points 1 and 2 you will need to choose a path. You will get the same answer no matter what path you choose.

2, [1pt] Calculate the work required to move a negative charge of q = ? 500 ? C from point 1 to point 2.

Explanation / Answer

1. V = E*r
V at point 2 is
V2 = V1 - E*r
V2 = 1200 - 56(12 - 7)
V2 = 920 V
2. W = qV
W = (-500 * 10^(-6)) (920 - 1200)
W = 0.14 J

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