Find the total energy stored in the electric field between the shells if the cha

Question

Find the total energy stored in the electric field between the shells if the charge on the inner shell is 2.3 meu C and the radii of the shells are 1 m and 2 m.The permittivity of a vacuum is 8.8542 times 10^-12 C^2/N m^2. Answer in units of mJ. 005 (part 4 of 4) 10.0 points Find the total energy stored in the electric field between the shells if the charge on the inner shell is 2.3 meu C and the radii of the shells are 1 in and 2 m. The permittivity of a vacuum is 8.8542 times 10^-12 C^2/N m^2. Answer in units of mJ. I tried to solve the problem and ended up with 24mJ also tried 23 but no luck and it said it was incorrect Please only respond if you are sure you know what you are doing, please include the answer and work out the problem step by step!

Explanation / Answer

E = Q/(40)*/r^2

E-field energy density = E^2 * (0/2)

Therefore, the integrated energy is:
(0/2)*(Q/(40))^2 (1/r^4) r d dr = (0/2)*(Q/(40))^2 (4) dr/r^3
= (Q^2/2)/(40) * [- 1/(2*r^2)] [r = 1, 2]
= (Q^2/(40)) * (1/1^2 - 1/2^2)/2
= (2.3e-6)^2/(4*8.85e-12*pi)*(1/1^2 - 1/2^2)/2
= (2.3^2/(4*8.85*pi))*(1/1^2 - 1/2^2)/2
= 17.84e-3 (J)
= 17.84 (mJ)

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