The thick lined box in the picture is a battery with emf 12v and internal resist

Question

The thick lined box in the picture is a battery with emf 12v and internal resistance. I ohm. A is the positive terminal and B is the negative terminal. What is the potential difference across the battery's terminals (A,B) when the switch $ is open? What is the potential difference across the battery's terminals when the switch $ is closed? Find the current through each of the resistors in the circuit below. Give both the magnitude and direction of current flow. Give answers in form ""3.5Amps Right" or "2.25Amps Left"

Explanation / Answer

8) 12 Volts

V_terminal = V_emf - I*r

here I = 0

so,V_terminal = Vemf

= 12 volts

9) 11.25 volts

when switch is closed,

I = V_emf/Rnet

= 12/(1+15)

= 0.75 A

so, V_terminal = Vemf - I*r

= 12 - 0.75*1

= 11.25 volts

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