How would you find the distance x a block would move to dissipate the energy, if

Question

How would you find the distance x a block would move to dissipate the energy, if it with the bullet and the bullet remains embedded in the block? The bullet is .012kg and the box is 2 kg the initial velocity was 300 m/s and the Kendrick friction on the table is .4 How would you find the distance x a block would move to dissipate the energy, if it with the bullet and the bullet remains embedded in the block? The bullet is .012kg and the box is 2 kg the initial velocity was 300 m/s and the Kendrick friction on the table is .4

Explanation / Answer

using Work energy theorem

Work done by the net force = change in KE

(-fk)*x = 0 - 0.5*m*u^2

fk is the kinetic frictional force = mu_k*N = mu_k*m*g

mu_k*(m+M)*g*x = 0.5*m*u^2

x = 0.5*0.012*300^2/(0.4*(0.012+2)*9.81) = 68.4 m

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.