An elevator with a 54-kg passenger is moving down at a speed of 12m/s. The eleva

Question

An elevator with a 54-kg passenger is moving down at a speed of 12m/s. The elevator comes to a halt over 25m at a constant rate. The passenger is on a bathroom scale as this occurs. What is the reading on the scale while the elevator is slowing down? [ NOTE: the scale only reads units of newtons] An elevator with a 54-kg passenger is moving down at a speed of 12m/s. The elevator comes to a halt over 25m at a constant rate. The passenger is on a bathroom scale as this occurs. What is the reading on the scale while the elevator is slowing down? [ NOTE: the scale only reads units of newtons]

Explanation / Answer

solution:

V2f =V2i +2as

here Vf =0 at halt position

Vi =12 m/s ;s =25 m

a =-V2i / 2s =122/ 2(25) =-2.88 m/s2

F =m(g+a) = m(9.8-2.88) = 54(6.92) = 373.68 N ans

so the reading of elevator will be 373.68 N

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