A proton is released such that its initial velocity is from right to left across

Question

A proton is released such that its initial velocity is from right to left across this page. The proton's path, however, is deflected in a direction toward the bottom edge of the page due to the presence of a uniform magnetic field. What is the direction of this field? out of the page into the page from bottom edge to top edge of the page from right to left across the page An electron has velocity v in the plane of the page. There is a uniform magnetic field pointing out of the page. Draw the trajectory' of the electron (be sure to use an arrow to indicate the direction of motion. There is a current I flowing in a clockwise direction in a square loop of wire that is in the plane of the paper. If the magnetic field B is toward the right, and if each side of the loop has length L. then the magnitude of the net magnetic torque acting on the loop is?

Explanation / Answer

3a) Option b is correct.

Right hand rule. Deflecting towards the bottom means there is a force pointing towards the bottom. Index finger pointing left, thumb pointing down, you find that the magnetic field (middle finger) points into the page.

3c) Torque = NBIA*sin(theta)

As N = 1, and sin(theta) = 1

Torque = BIA = BIL^2 [as A = L^2]

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