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help with number 2 please Two equally charged particles held 41.4 cm apart are r

ID: 1427413 • Letter: H

Question

help with number 2 please

Two equally charged particles held 41.4 cm apart are released from rest. The initial acceleration of the first part observed to be 7.0 m/s^2 and that of the second particle is 4.0 m/s^2. If the mass of the first particle is 12.4 Times 10^-7 kg determine the of the second particle in kg Then determine the charge on the particles Two hypothetical point particles, particle A, comprised of 6 electrons and a proton and the particle B comprised of protons and an electron are separated by a distance of 7.8 nm to form an electric dipole. The dipole moment vector has magnitude C.m and points from particle to particle Then choose the correct answer below. The electric potential difference between the ground and a cloud in a particular thunderstorm is 1.2 Times 10^12 V. What is magnitude of the change in the electric potential energy of a particle, whose charge is (2.7 times 10^15) e, that moves between these points (i.e., between the ground and the cloud)? (See Figure below) Consider a point charge q = + 1463 nC, a point A (which is 438.5 nm distant from q), and a point B (which is 372.5 nm distant from q) If these Points (A and B) are diametrically opposite each other what is the potential difference V_A - V_B = ? Put your answer in the form unit " Unit " refers to symbol for the unit for electrical potential in the SI system of measurements. A flat parallel plate capacitor has circular plate of 75.3 cm radium and 0.08 nm separation. Calculate the capacitance What charge will appear on the capacitor plates if a potential difference of 9.0 V is applied to it? The "plates" of a spherical capacitor have radii 8.60 cm and 9.5 cm. The space between the two spheres is filled with a material with dielectric constant of 15.0. Calculate the capacitance.

Explanation / Answer

1) Correct option is (c)

F1 =F2

m1a1 =m2a2

m2 = (12.4*10^-7*7)/4 = 2.17*10^-6 kg

Correct option is (a)

k =9*10^9 N.m^2/C^2, d = 41.4 cm

m1a1 = kq^2/d^2

q^2 = (12.4*10^-7*7(0.414*0.414)/(9*10^9)

q =1.28*10^-8 C

2) Correct option is (d)

dipole moment = q*l = 5*1.6*10^-19 * 7.8*10^-9

p = 6.24*10^-27 C.m , A to B (negative to positive)


3) Correct option is (b)

V =1.2*10^12 V, q =2.7*10^15e , e =1.6*10^-19C

U =qV = 2.7*10^15*1.6*10^-19*1.2*10^12

U = 5.19*10^8 J


4) Correct option is (e)


5) Correct option is (d)

C =Aeo/d = (3.14*0.753*0.753*8.85*10^-12)/(0.08*10^-3)

C =1.97*10^5 pF


6) Correct option is (a)

r1 =8.6 cm , r2 = 9.5 cm

k =15

C =4pi*eo*k(r1r2)/(r2 - r1)

C= (4*3.14*8.85*10^-12*15*0.086*0.095)/(0.095-0.086)

C= 1.5*10^-9 F