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help asap #3 with d arrow physics Answer: () 1.2s10%-s)c. (b) 3.72x10-9)c (e)1.2

ID: 1427396 • Letter: H

Question

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#3 with d arrow
physics

Answer: () 1.2s10%-s)c. (b) 3.72x10-9)c (e)1.2810*%-4) nC (d)926x106-6)c (s2c 2) (10 points): Two hypothetical point particles, particle A. comprised of 6 electrons snd protons and an electron proton sndthe particle B comprised of 6 are separated by a distance of 7.8 nm to form an electric dipole. The dipole moment vector has magitude Cm and points from particle to particle- Then choose the correct answer below Answer: (a) 5.23 x 10X-22), A>B. (b) 5.23 x 10x-22), B>A. (c)6.25 x 10 (-2T), B>A. (d) 6.25 x 10%-27), A-B (0 (9 points): The electric potential difference between the ground and a cloud in a particular thunderstorm is 1.2x 10*v. What magnitude of the change in the electric potential energy of a particle, whose charge is (2.7x 10"e, that moves between these po Answer: (a) 8.26x1015)J. (b) 5.19x10 8) J. (c) 6.22x106)J. (d)3 I101. ()62210101. (40 3.1910)m. 0 benween the ground and the cloud)? aerte 4) (10 points): (See Figure below) Consider a point charge q-+ 163 nC, a point A (which is 438.5 mm distant from q) and (which is 372.5 nm distant from q). If these points (A and B) are diametrically opposite each other, what is the potential dif VA-Vs Put your answer in the form "+/-a.bc x 10x) unit". "Unit" refers to symbol for the unit for electrical potential system of measurements. nswer: (a) 5.93x1018)V. (b-7.67x1013. (c)7.67x10Ys)v. (d)-5.93x10 8). (e93x10(8)V. (0

Explanation / Answer

U = q*dV

where q = 2.7*10^15*e = 2.7*10^15*1.6*10^-19 = 4.32*10^-4 C

dV = 1.2*10^12 V

U = 4.32*10^-4*1.2*10^12 = 5.184*10^8 J = 5.19*10^8 J