1. Two blocks of masses m and 2 m are held in equilibrium on a frictionless incl
ID: 1427106 • Letter: 1
Question
1. Two blocks of masses m and 2m are held in equilibrium on a frictionless incline as in the figure. In terms of m and , find the following. (Use any variable or symbol stated above along with the following as necessary: g.)
(a) the magnitude of the tension T1 in the upper cord
T1 =
(b) the magnitude of the tension T2 in the lower cord connecting the two blocks
T2=
2. A 1,170-kg car is pulling a 280-kg trailer. Together, the car and trailer have an acceleration of 2.00 m/s2 in the positive x-direction. Neglecting frictional forces on the trailer, determine the following. (Indicate the direction with the sign of your answer. Take the forward direction to be positive. Assume the trailer's weight is entirely supported by it's own tires.)
(a) the net force on the car
in N
(b) the net force on the trailer
in N
(c) the force exerted by the trailer on the car
in N
(d) the resultant force exerted by the car on the road
Explanation / Answer
The tension in the upper cord is:
T = (m + 2m)×9.8×sin()
T = 29.4×m×sin()
To find the tension in the lower cord, you need to know which is the lower block.
If it is the block with mass m, then
T = 9.8×m×sin()
If it is the block with mass 2m, then
T = 19.6×m×sin()
2.The car generates the force to accelerate the pair
F=(1170+280)*2.0
F=2900 N
a) Net force on the car is
1170*2
2340 N
b) The trailer
280*2
560 N
c) -280*2
-560 N
d) sqrt(2900^2+(1170*9.81)^2)
11838.4 N
direction is
atan(1170*9.81/2900)
75.28degrees above horizontal
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