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Four identical metallic spheres with charges of +7.8 µC, +6.6 µC, 8.6 µC, and 3.

ID: 1426888 • Letter: F

Question

Four identical metallic spheres with charges of +7.8 µC, +6.6 µC, 8.6 µC, and 3.2 µC are placed on a piece of paper. The paper is lifted on all corners so that the spheres come into contact with each other simultaneously. The paper is then flattened so that the metallic spheres become separated.

(a) What is the resulting charge on each sphere? _____.65_____ µC

GOT PART A NEED HELP WITH WHAT THE ANSWER IS FOR PART B

(b) How many excess or absent electrons (depending on the sign of your answer to part (a)) correspond to the resulting charge on each sphere?

__________ electrons are ---Select--- absent or in excess (a)   answer is not 0.40625e-13

Explanation / Answer

(a) Being identical spheres the net charge will be shared equally ..
Net charge = + 8.60 C .. (8.60^-6 C)

Charge on each sphere = +2.6.C / 4 .. +0.65 C each

(b) ne = +0.65^-6C .. .. n = number of absent electrons each with charge e

n =0.65^-6C / 1.6.^-19 C/e .. .. n = 0.4065^13 absent electrons (giving +ve charge)

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