In an experiment, it is seen that an incline of 30^degree with respect to the ho

Question

In an experiment, it is seen that an incline of 30^degree with respect to the horizontal will cause a 2.0 kg box to just begin sliding down a ramp. For this setup. Now imagine the incline is reduced to 15^degrees 1 What is the magnitude o(the normal force acting on the box now? What is the friction force(type, magnitude, and direction)acting on the box Now set the angle of the incline to 45^degrees with respect to the horizontal. What is the magnitude of the normal force acting on the box now? What is the magnitude of acceleration of the box?

Explanation / Answer

1) Normal force = N = mg*sin = 2*9.8*sin30 = 9.8 N (perpendicular to incline surface)

2) The frictional force = Ff = * m * g * cos = 0.25 * 2 *9.8* cos 30 = 4.24 N (upward, parallel to incline plane)

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