1. A 8.6 µF capacitor is charged by a 9.00 V battery through a resistance R . Th
ID: 1426104 • Letter: 1
Question
1. A 8.6 µF capacitor is charged by a 9.00 V battery through a resistance R. The capacitor reaches a potential difference of 4.20 V at a time 3.09 s after charging begins. Find R.
2. A 2.02 nF capacitor with an initial charge of 4.55 µC is discharged through a 1.22 k resistor.
(a) Calculate the current in the resistor 9.00 µs after the resistor is connected across the terminals of the capacitor.
(b) What charge remains on the capacitor after 8.00 µs?
(c) What is the maximum current in the resistor?
Explanation / Answer
q = Q * (1 - e^(-t/RC))
8.6*4.20 = 8.6*9.0 * (1 - e^(-3.09/RC))
RC = 4.92
R = 4.92/(8.6*10^-6) ohm
R = 5.72 * 10^5 ohm
please post seperate questions in seperate post only.
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