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WileyPLUS x Chegg Study | Guided Sol C-edugen.wileyplus.com/edugen/student/mainfr.uni WileyPLUS cutnell, Physics, 10e GENERAL PHYSICS Home Read, Study& Practice t Assignment GradebookORION Assignment > Open Assignment FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES hapter 24 Homewor Question 8 For one approach to this problem, consult Interactive LearningWare 24.1. For each of the three sheets of polarizing material shown in the drawing, the orientation of the transmission axis is labeled relative to the vertical. The incident beam of light is unpolarized and has an intensity of 1300 w/m2, what is the intensity of the beam transmitted through the three sheets when | 18.4°, 2 = 47.0°, and 3 = 97.207 l e F Question 4 Transmitted beam Vertical uestion 8 2 Incident beam Review Score ul Objective Number Units the tolerance is +/-390 SHOW HINT LINK TO TEXT Question Attempts: O of 3 used SAVE FOR LATER SUBMIT ANSWER Privacy Policy All Rights Reserved. A Division of Version 4.17.3.3 G 6:03 PM , 2/29/2016

Explanation / Answer

According to Malus’s law,
Intensity of Light Passing through polarizer is given by,

I = Io*cos^2()

Io = 1300 W/m^2
From 1st Polarizer
I = 1300 * cos^2(18.4)
I = 1170.5 W/m^2

From 2nd Polarizer
I = 1170.5 * cos^2(47.0 - 18.4)
I = 1170.5 * cos^2(28.6)
I = 902.3 W/m^2


From 3rd Polarizer
I = 902.3 * cos^2(97.2 - 47)
I = 902.3 * cos^2(50.2)
I = 369.7 W/m^2

Final Intensity of Light, I = 369.7 W/m^2

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