A TT Internship Jobs, Employ... X Homework 5 Circular Kin... x A wheel 0.46 m in

Question

A TT Internship Jobs, Employ... X Homework 5 Circular Kin... x A wheel 0.46 m in radius ro... x Whenever two Apollo astro... x 3 b/Student/Assig dep-13131534 TT 21TT (4 2) (1.496 x 10 m) 1 yr Substitute numerical values 3.156 x 10 s (1 yr) a, 0.005952 m/S Finalize This acceleration is much smaller than the free-fall acceleration on the surface of the Earth. An important thing we learned here is the technique of replacing the speed v in Equation (1 n terms of the period Tof the motion.In many problems, it is more likely that T s known rather than v. HINTS GETTING STARTED I M STUCK! MASTER IT A wheel 0.46 m in radius rotates at a constant rate of 100 rev/min. Find the speed and acceleration of a small stone lodged in the tread of the tire (on its outer edge). m/s m/S Watch a Video Hint Need Help? Read it Talk to a Tutor Search 2:45 PM 2/29/2016

Explanation / Answer

o = 100 rev/min =100 * 2/60 = 10.47 rad/s

v=ro =0.46*10.47=4.815 m/s

a=v^2/r= 4.815^2/0.46=50.4 m/s^2

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