The figure shows the path of a negatively charged part.clo region of a uniform m
ID: 1425380 • Letter: T
Question
The figure shows the path of a negatively charged part.clo region of a uniform magnetic field. What is the direction of the magnetic field in the shaded region? If we double the speed of the particle, how will the path change? If we double the magnitude of the uniform magnetic field, how will the path change? If we replace the original particle with a negative particle of twice the charge and the same mass, how will the path change? If we replace the original particle with a positive particle of the same mass and same magnitude charge as the original negative charge, how will the path change? If we replace the original particle with a negative particle of twice the mass and the same charge, how will the path change? A current carrying loop (I = 0.6A) is placed in a uniform magnetic field (B = 0.5T) as shown in the figure. Each side of the loop is 80cm long. Determine the magnitude and direction of the magnetic force on each side of the loop. Determine the magnitude and direction of the net magnetic force on the loop.Explanation / Answer
3. Magnetic force provides centripetal acceleration,
mv2/R = qvB
In this case,
mv2/R = -qvB since charge is negative,
(a) To provide such a centripetal acceleration, -q(v×B) must points towards center of curvature of traversed path. For that to occur, B must be pointing out of the screen.
(b) R = -qB/mv
If v is doubled, radius of curavture gets halved.
(c) R = -qB/mv, If B is doubled, radius of curvature gets doubled.
(d) if q is doubled, radius of curvature gets doubled.
(e) If charge becomes +q, R = qB/mv, instead of moving up, particle will move down with same radius of curvature since direction of magnetic force (q(v×B)) is reversed.
(f) R = -qB/mv, If m is doubled, radius of curavture gets halved.
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