1. two particles with equal mass, one carrying a charge q and the other -2q each

Question

1. two particles with equal mass, one carrying a charge q and the other -2q each enter at right angles to a uniform magnetic field with the same velocity. which is deflected into a circular path with the larger radius?

2. A rectangular current-carrying loop of wire is in a uniform magnetic field with a magnitude of 0.10 T as show in the figure below. The current flowing through each loop is 0.250 A. What are the direction and magnitude of the magnetic force acting on each section of the wire?

Sorry I don't know how to put up the picture. Basically its a rectangle like this and the length is 5 cm. There are also an array of dots on the right hand side of the rectangle but I suppose that just illustrates the magnetic field

<---- I

Explanation / Answer

1. Magnetic force provides centripetal accleration,

qvB = mv2/R

R = mv/qB

So R is inversely proportional to charge.

Therefore,charge q will have more radius than charge -2q.

2. F = I(L×B)

dot means magnetic field is pointing out of the screen.

On the upper part part of the wire, I is flowing in left direction, So F = 0.25*0.1*0.05 = 1.25*10-3 N pointing upwards.

On the bottom part part of the wire, I is flowing in right direction, So F = 0.25*0.1*0.05 = 1.25*10-3 N pointing downwards.

For left and right part of the wire, width of the rectangle is required which is not given here. Anyways, force on left part will be in left direction and  force on right part will be in right direction

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.