Eskir is pulled by a tow rope i\'ll put the frictionless ski slope that\'s makes

Question

Eskir is pulled by a tow rope i'll put the frictionless ski slope that's makes an angle of 17° with the horizontal. The rope moves parallel to the slope with a constant speed of 1.1 m/s. The force of the rope does 510 J of work on the skier as the skier moves a distance of 4.1 m up the incline. (A) if the rope moved with a constant speed of 2.2 m/s, how much work would the force of the rope do on the skier as the skier moved a distance of 4.1 m up the incline? At what rate is the force of the rope doing work on the skier when the rope movies with a speed of (b) 1.1 m/s and (c) 2.2 m/s Eskir is pulled by a tow rope i'll put the frictionless ski slope that's makes an angle of 17° with the horizontal. The rope moves parallel to the slope with a constant speed of 1.1 m/s. The force of the rope does 510 J of work on the skier as the skier moves a distance of 4.1 m up the incline. (A) if the rope moved with a constant speed of 2.2 m/s, how much work would the force of the rope do on the skier as the skier moved a distance of 4.1 m up the incline? At what rate is the force of the rope doing work on the skier when the rope movies with a speed of (b) 1.1 m/s and (c) 2.2 m/s

Explanation / Answer

a) 510J

Work does not depend upon time so the rope does the same amount of work

b) Power = F*v = W/d *v = 510J/4.1m*1.1 m/s = 136.829 = 137W or j/s

c) Power = F*v = W/d*v = 510J/4.1m*2.2m/s = 273.658 = 274W or j/s

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