In a region containing an electric field, point A is at 750 volts and point B is

Question

In a region containing an electric field, point A is at 750 volts and point B is at 950 volts. An electron is observed moving at some speed at point A. When it reaches point B, will the electron's speed have increased, or stayed the same? Explain your answer. A proton is accelerated from rest through a voltage difference of 1500 V. What is its final speed? A proton has a velocity of 10 times 10^5 m/s when observed at point A and a velocity of 3.0 times 10^5 m/s when observed at point B. If the voltage at point A is 1000 volts, what is the voltage at point B?

Explanation / Answer

W = q delV

from the conservation of energy

W = KE

q delV = 1/2 mv^2

v = sqrt 2q de V/ m

speed of electron is directily proportional to square root of voltage

since voltage is increasing speed also increases

v = sqrt 2( 1.6 * 10^-19 C) (950 V- 750 V)/ 1.6726219 × 10-27 kilograms

=19.56 * 10^4 m/s

v1 = sqrt V1

v2= sqrt V2

v2/v1 = sqrt(V2/V1)

V2 = V1 (v2/v1)^2

=1000 (3* 10^5/1* 10^5)^2

=9000 V

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