As shown in the figure below, a coil that is square, has 30 turns, is 0.82 ?, an
ID: 1424887 • Letter: A
Question
As shown in the figure below, a coil that is square, has 30 turns, is 0.82 ?, and is 15.0 cm on a side is between the poles of a large electromagnet that produces a constant, uniform magnetic field of 0.5 T directed into the page. As suggested by the figure, the field drops sharply to zero at the edges of the magnet. The coil moves to the right at a constant velocity of 4.00 cm/s. What is the current through the coil wire in the following instances?
(b) while the coil is leaving the field
(c) after the coil leaves the field
(d) What is the total charge that flows past a given point in the coil as it leaves the field?
lv B into the page 30-turn coilExplanation / Answer
a)
change in flux =0
emf = 0
curret i = E/R = 0
(b)
E = rate of change in flux = N*B*l*V
current = i = E/R = (30*0.5*0.15*0.04)/0.82 = 0.11 A
(c)
as the coil leaves the field the flux is zero
so emf = 0
i= 0
(d)
Q = i*t = i*L/v = 0.11*0.15/0.04 = 0.4125 C
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