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1) What is E y (R), the y-component of the electric field at point R, located a

ID: 1424534 • Letter: 1

Question

1)What is Ey(R), the y-component of the electric field at point R, located a distance d = 43 cm from the origin along the y-axis as shown?

2) What is V(P) – V(R), the potential difference between points P and R? Point P is located at (x,y) = (43 cm, 43 cm).

3)What is V(c) - V(a), the potentital difference between the outer surface of the conductor and the outer surface of the insulator?

4) The charge density of the insulating cylinder is now changed to a new value, ?’ and it is found that the electric field at point P is now zero. What is the value of ?’?

R(0,d) Pad)

Explanation / Answer

1.
charge: Q= *a^2*pi
then, the electric field is,
E(R)=((lambda)+Q)/(r*2*pi*8.85e-12) , r= 0.43 m

2.
distance P = SQRT(0.43^2+0.43^2)
then the potential difference:
V(P)-V(R)= (((lambda)+Q)/(2*pi*8.85e-12))ln(P) - (((lambda)+Q)/(2*pi*8.85e-12))ln(R) ,where R= 0.43 m

3. calculate the potential difference as follows:
V(c)-V(a)= -(Q/(2*pi*8.85e-12))int[(1/r)dr] , limits: a to b

= -(Q/(2*pi*8.85e-12))ln{a/b}

4.

the value of is calculated as follows:

0= (lambda+(*a^2*pi))/(2*pi*r*8.85e-12)

substitute the data in each subpart and solve the required results.