A bar magnet is released and consequently \"freefalls\" through a closed conduct

Question

A bar magnet is released and consequently "freefalls" through a closed conducting loop. Assume that:

Clockwise current, as viewed from above the loop, is taken to be positive current and counter clockwise current is taken to be negative.

At time t = tm, the magnet is exactly half way through the loop.

The motion of the bar magnet is unaffected by the induced current in the loop. That is, its motion is "freefall" motion and is accelerating.

Which of the plots below indicates most correctly the induced current in the loop? As always, briefly defend your choice.

Explanation / Answer

option

A

will be your answer.

1) when you bring N pole closer to loop, flux will increase so it produces current in a way to reduce flux so the loop will behave like the north pole it means current in anti-clockwise or according to question in negative direction .

2 ) at middle both cancel each other effect ,because it have both effect flux increasing and decreasing so one time will come where both will be equal so net I= 0 at T= tm

3) and at last it will behave exactly opposite to first one but since it already gains velocity so it will go faster than first one so less area under curve

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