A projectile is shot from a platform at point O as shown in the figure below, wi

Question

A projectile is shot from a platform at point O as shown in the figure below, with an initial launch angle of theta_2 = 35 0 degree, and an initial speed v_0 = 12.0 m/s (gravitational acceleration is g = 9 80 m/s^2) The projectile just clears the edge of the platform at point B and lands on the ground h = 5.00 m below at point C. What are the x and y-component of the projectile s initial velocity? Calculate the time t_OA it takes the projectile to go from point O to point A Calculate the height H of the highest point (A) of the trajectory Calculate the distance d between the launch point O and the edge of the platform at point B Calculate the time t_OC it takes the projectile to go from point O to point C. What is the speed v of the projectile when it hits the ground at point C?

Explanation / Answer

Here ,

a) for the x and y components

x -component of initial velovity = vo * cos(35)

x -component of initial velovity = 12 * cos(35)

x -component of initial velovity = 9.83 m/s

y - component of initial velocity = v0 * sin(theta)

y - component of initial velocity = 12 * sin(35)

y - component of initial velocity =6.88 m/s

b) let the time taken is t

time taken to reach A = vy/g

time taken to reach A = 6.88/9.8

time taken to reach A =0.792 s

the time taken to reach A is 0.792 s

c)

for the highest H

H = Vy^2/(2 *g)

H = 6.88^2/(2 * 9.8)

H = 2.415 m

the maximum height H is 2.415 m

d)

for the distance d

d = v0^2 * sin(2 * theta)/g

d = 12^2 * sin(2 * 35)/9.8

d = 13.81 m

the distance d is 13.81 m

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