A jet airliner moving initially at 3.80 Times 10^2 mi/h due east enters a region

Question

A jet airliner moving initially at 3.80 Times 10^2 mi/h due east enters a region where the wind is blowing at 1.00 Times 10^2 mi/h in a direction 28.0 degree north of east. (Let the x-direction be eastward and the y-direction be northward.) Find the components of the velocity of the jet airliner relative to the air, V_JA. Find the components of the velocity of the air relative to Earth, V_AE. Write an equation analogous to V_AB = V_ae - V_be for the velocities V_ja, V_ae, and V_jE. (In the given equation, V_be is the velocity of observer B relative to observer E. Object A travels with velocity V_ab relative to observer B, and velocity V_ae relative to observer E. What are the speed and direction of the aircraft relative to the ground?

Explanation / Answer

a) Relative to the air, the aircraft is doing 380mph. east. That doesn't change.

b) A wind of 100mph blowing 28 deg. N of E has components of (cos28 x 100) = 88.29 mph east, and (sin28 x 100) = 46.94 mph north.

d) For every hour it flies, the aircraft will be accelerated by 88.29 mph, so 468.29 miles is the east component, and 46.94 miles is the north component.

Speed over the ground is sqrt (468.29^2 + 46.94^2) = 470.63 mph.
The flight direction will be ( 46.94 / 468.29) = tan L, so tan-1(0.100) = 5.72deg.,N of E

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.