A particle has a charge of q = +5.2 ?C and is located at the origin. As the draw

Question

A particle has a charge of q = +5.2 ?C and is located at the origin. As the drawing shows, an electric field of Ex = +234 N/C exists along the +x axis. A magnetic field also exists, and itsx and y components are Bx = +1.6 T and By = +1.3 T. Calculate the force (magnitude and direction) exerted on the particle by each of the three fields when it is (a) stationary, (b)moving along the +x axis at a speed of 345 m/s, and (c) moving along the +z axis at a speed of 345 m/s.

(a) FE = .001217 N

FBx =

FBy =

(b) FE =

FBx =

FBy =

(c) FE =

FBx =

FBy =

FBx =

FBy =

(b) FE =

FBx =

FBy =

Explanation / Answer

a) FE = QE = 5.2*10^-6*234 = 1216.8*10^-6 N

FB = Q(V*B) = 0

B) FE = 1216.8*10^-6 N

FB = Q(V*B) = Q(345 i*1.6i+1.3j) = 5.2*10^-6(0+345*1.3 k)

fbz = 0.00233 k N

fbx = fby = 0

c)FE = 1216.8*10^-6 N

FB = 5.2^10^-6(345 k*1.6i+1.3j) = 5.2^10^-6(552j+448.5(-i))

fbx = -0.00233 N

fby = 0.00287 N

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