Two students, A and B, leave LIU together, walking down Flatbush Ave to Atlantic

Question

Two students, A and B, leave LIU together, walking down Flatbush Ave to Atlantic Terminal. Two minutes into the trip, student A stops for 3 minutes to buy coffee at Starbuc while student B continues walking. Student A then catches up with student B, 2 minutes after Starbucks, but he doesn't see Student B and passes right by her. The graph below shows the of the students, labeled A and B, as a functions of time. Seven minutes in lo the trip (at t = 7 min), are the velocities of the students equal? If which is larger? For the first 7 minutes of the trip (from t = 0 to t = 7 min), are the average velocities the students equal? If not, which is larger? For the time between t =1 min and t = 3 min is the average acceleration of student A positive, negative, or zero? For the time between t = 1 min and t = 3 min is the average acceleration of student B positive, negative, or zero?

Explanation / Answer

a) the velocity is equivalent to the slope in a x vs t graph, at t=5 A has a greater slope menaing that A has a larger velocity

b) Since they coincide at 7 min from 0 to 7 min they have the same average velocity (X=V_aveT)

c) and d) Since this is a position vs time graph the acceleration is present if the form of this type of graph is parabollic (2nd grade polynomics). In this case both A and B have linear displacements meaning that the velocity is constant so for both A and B the acceleration is zero

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