The graph shows the potential energy of a 10pC test charge moved radially inward
ID: 1422172 • Letter: T
Question
The graph shows the potential energy of a 10pC test charge moved radially inward toward the center of a molecule. The test charge has a mass of 250µg.
a) What is the magnitude and direction of the electric field at r = 100nm?
b) The test charge is released at r = 190nm. How fast and in what direction is it moving after undergoing a 10nm displacement?
c) Are there any points of stable static equilibrium? Support your answers wth explanations and/or calculations.
Electrostatic Potential Energy vs. Radial Distance 2 3.E+059 o.E+00% 220 200 180 160 140 120 100 80 60 40 200 Distance in nanometersExplanation / Answer
a) magnitude and direction of the electric field = 8.01*10-14 / 100 *10-9 *10*10-12
= 8.01 *104 N/C
Direction = radially inward
b) change in potential energy = 1.602*10-14 J
=> v = sqrt(2*1.602*10-14/250 * 10-9)
= 3.58 * 10-4 m/sec -------------------> radially inward
c) points are there for stable static equilibrium .As between 130 µm and 140 µm points are the points where the net electric field is zero .This can be seen in the graph as potential energy have reached maximun value .
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