A files jumps by exerting a force of 1.27 time sign 10.5^-5 N straight down on t

Question

A files jumps by exerting a force of 1.27 time sign 10.5^-5 N straight down on the ground. A breeze blowing on the flea parallel to the ground exerts a force of 1.20 time signs 10^-6 N on the flea. Find the direction and magnitude of the acceleration of the flea if its mass is 6.0 time signs 10^-7 kg. (Let us assume that F_mind points to the right. We will consider this to be the +x direction and vertical to be the +y direction.) magnitude 11.37 m/s^2 direction 29.62 Review vector components. In which of the four questions is the resultant force located?" (measured downward from the vertical)

Explanation / Answer

a)

mass of the flea m=6*10^-7 kg

downward force on flea, F1=1.27*10^-5 N

force due to breeze on the flea, F2=1.2*10^-6 N

net force along y axis,

Fy=F1-m*g

Fy=(1.27*10^-5)-(6*10^-7*9.8)

Fy=6.82*10^-6 N

and

net force along x axis,

Fx=F2

Fx=1.2*10^-6 N

net force magnitude Fnet=sqrt(Fx^2+Fy^2)

Fnet=sqrt((6.82*10^-6)^2+(1.2*10^-6)^2))

Fnet=6.92*10^-6 N

magnitude of acceleration,

a=Fnet/m

a=6.92*10^-6/(6*10^-7)

a=11.53 m/sec^2

b)

direction is,

tan(theta)=Fy/Fx

tan(theta)=(6.82*10^-6)/(1.2*10^-6)

=====> theta=80.02 degrees with respect to horizontal

or

theta=9.98 degrees with respect to vertical

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