(b) If the particles are still initially held 8.00 nm apart but both particles a
ID: 1421752 • Letter: #
Question
(b) If the particles are still initially held 8.00 nm apart but both particles are released, when they are 5.76 nm away from each other, how would Particle I's speed compare to the speed used in part (a) above? (Assume that Particle II's mass is not the same as Particle I's; you should be able to answer this without performing a detailed calculation.)
A. Particle I would be faster than it was in (a)
B. Particle I would be moving at the same speed that it had in (a)
C. To answer this at all, Particle II's mass would be needed
D. Particle I's speed is unknown but it will definitely be the same as Particle II's
E. Particle I would be slower than it was in (a)
Explanation / Answer
a)
let
q1 = +q
q2 = -q
m1 = 1.04*10^-22 kg
d1 = 8 nm
d2 = 5.76 nm
v1 = 51 km/s
Apply conservation of energy
Ki + Ui = Kf + Uf
0 + k*q1*q2/d1 = (1/2)*m1*v1^2 + k*q1*q2/d2
-k*q^2/d1 = (1/2)*m1*v1^2 -k*q^2/d2
k*q^2*(1/d2 - 1/d1) = (1/2)*m1*v1^2
q = sqrt(0.5*m1*v1^2/(k*(1/d2 - 1/d1)) )
= sqrt(0.5*1.04*10^-22*51000^2/(9*10^9*(1/(5.76*10^-9) - 1/(8*10^-9) ) ) )
= 5.56*10^-16 C <<<<<<<<<----------Answer
b) A. Particle I would be faster than it was in (a)
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