Two horizontal forces, P and Q , are acting on a block that is placed on a table

Question

Two horizontal forces, P and Q , are acting on a block that is placed on a table. We know that P is directed to the left but the direction of Q is unknown; it could either be directed to the right or to the left. The object moves along the x-axis. Assume there is no friction between the object and the table. Here P = 2.7 N and the mass of the block is 4.3 kg. (a) What is the magnitude and direction of Q when the block moves with constant velocity? (Indicate the direction with the sign of your answer.) N (b) What is the magnitude and direction of Q when the acceleration of the block is +5.7 m/s2. (Indicate the direction with the sign of your answer.) N (c) Find the magnitude and direction of Q when the acceleration of the block is 5.7 m/s2. (Indicate the direction with the sign of your answer.) N

Explanation / Answer

here

(a)since both act in Horizontal direction

P+Q = 0

P = -Q = -(-2.7)

Q = + 2.7 N (ANSWER)

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(b) Q = mg + F

Q = (4.3*5.7) + 2.7

Q = = +27.21 N (ANSWER)

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(c) Q =mg - F

Q =   (4.3*5.7) - 2.7

Q = -21.81 N (ANSWER)

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