. In 1971, U.S. astronaut David Scot conducted a simple, yet famous experiment o

Question

. In 1971, U.S. astronaut David Scot conducted a simple, yet famous experiment on the surface of the moon, where a = 1.62 m/s^2 is the magnitude of the gravitational acceleration, and there is no atmosphere. Specifically, he dropped a hammer and a feather from rest at the same height above the ground. Assuming that he released the hammer from a height of 1.55 m above the moon’s surface, how fast was the hammer moving when it hit the ground? The answer is, V=2.24 m/s. What are the steps to solving this problem?

Explanation / Answer

v2 - u2 = 2ah here u = 0 m/s a = 1.62 m/s2 h = 1.55 m

v2 - 0 = 2 x 1.62 x 1.55

v = 2.241 m/s

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