A) Given that the ratio of delta Q / delta V is fixed, when you change the volta

Question

A) Given that the ratio of delta Q / delta V is fixed, when you change the voltage where does the charge change come from? Note. Charge does not flow through a good dielectric i.e. there is no mass transport of coulombs.

B) Other than calculating each point how could we determine the direction of travel of a wave?

C) Given that the ratio of delta Q / delta V is fixed, when you change the voltage where does the charge change come from? Note. Charge does not flow through a good dielectric i.e. there is no mass transport of coulombs.

Please answer each with a few senetences

Explanation / Answer

we know that

Q=C*V

dQ = C*dV

here c is fixed and its a constant

that means

dQ is directly protional to dV

so charge change will be there for change in Voltage. and this change depends upon the speed of the moving electrons.

2)

For a specific area of the wave which is moving in any direction, the phase must be consistent. In this way, if the condition says y ( x , t ) = A cos ( t + x + ) , the term inside the cosine must be steady. Subsequently, if time expands, x must reduction to get that going.

Inverse of above happens when the condition says y(x,t)=Acos(tx+)y(x,t)=Acos(tx+). In the event that t increment, x must increase to compensate for it. That makes a wave moving in positive course.

The essential idea:For a moving wave, you consider a specific piece of it, it moves. This implies the same y would be found at other x for other t, and in the event that you change t, you have to change xxaccordingly.

Trust that makes a difference!

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