unread) whitn Mastering physics: Chapter 26 Homework Google Chrome https: gphy P
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unread) whitn Mastering physics: Chapter 26 Homework Google Chrome https: gphy PHYS 2220 Summer 16 Chapter 26 Homework Problem 26.29 Problem 26.29 at are the strength and direction of the electric field at ed b Figure 1 of 0 nC 4.0 cm 2.0 cm 5.0 nC 0 nC MasteringPhysics: Assign Resources e previous l 8 of 11 I next Part A Give your answer in terms of the horizontal and vertical components. Take the positive directions to be up and to the right. Express your answer using two significant figures. Enter your answers numerically separated by a comma. Ear, E N/C My Answers Give Up Part B Give your answer as a magnitude and angle measured from the positive x Express your answer using two significant figures. N/C My Answers Give Up Part C Express your answer using three significant figures NE CES 17 guestions remaining this subscription period COMPANY LEARNING SERVICES Chegg College Blog Online Tutoring Chegg Study Help EExplanation / Answer
Electric field due to -5 nC = k x 5 x 10^-9/ (2x10^-2)^2 (-j) = 11.25 x 10^-5 (-j)
electric field due to 10nc= k x 10 x 10^9/(4x 10^-2)^2 (-i) = 5.625 x 10^-5 (-i)
electric field due to 10nC= [k x 10 x 10^-9/(20x 10^-4) ] x{(4/4.47) (-i) + (2/4.47)j}
= 3.829 x 10^-5 (-i) + 1.914 x 10^-5j
a.so net x-component= Ex= 5.625 x 10^-5 (-i) +3.829 x 10^-5 (-i)= - 9.454 x 10^-5 i
net y-component = Ey= 11.25 x 10^-5 (-j) + 1.914 x 10^-5 j = -9.336 x 10^-5 j
b.so net electric field= E= sqrt( Ex^2 + Ey^2) = 13.28 x 10^-5 N/c
c.angle = tan inv( -9.336/-9.454) =91.28 degree clockwise from x-axis
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