(8%) Problem 1 2: A new landowner has a triangular piece of flat land she wishes
ID: 1419652 • Letter: #
Question
(8%) Problem 1 2: A new landowner has a triangular piece of flat land she wishes to fence. Starting at the west corner, she measures the first side to be 72 m long and the next to be 114 m. These sides are represented as displacement vectors A and B in the figure A BC- B 11 21° ©theexpert ta.com 100% Part (a) She then correctly calculates the length of the third side C. What is her result (in meters)? Grade Summary Potential 100% sino cotanasi atan cosh tanho coso asin( ) tano acoso acotan) sinhO tanh cotanh Attempts remaining: 4 56 per attempt) detailed view ODegrees Radians Hint I give up! Hints:deduction per hint. Hints remaining:2 Feedback: 0% deduction per feedback.Explanation / Answer
A) Y = 72 * SIN 21 = - 25.8
A) X = 72 * COS 21 = 67.22
B) Y = 114 * COS 11 = 111.9
B) X = 114 * SIN 11 = -21.75
TOTAL Y = 111.9 - 25.8 = 86.1
TOTAL X = 67.22 - 21.75 = 45.47
Third Side : C) = SQRT (86.1^2 + 45.47^2) = 97.37 Meters length
Third Side : C) Angle = ARC TAN 86.1/45.47 = 62.16 degrees North of Due West
from the West Corner
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