The portion of string between the bridge and upper end of the fingerboard (the p

Question

The portion of string between the bridge and upper end of the fingerboard (the part of the string that is free to vibrate) of a certain musical instrument is 60.0 cm long and has a mass of 2.14 g . The string sounds an A4 note (440 Hz ) when played.

Part A) Where must the player put a finger (at what distance x from the bridge) to play a D5 note (587 Hz )? (See the figure (Figure 1) ) For both notes, the string vibrates in its fundamental mode.

Part B) Without retuning, is it possible to play a G4 note (392 Hz ) on this string?[Yes it is possible to play or No it's impossible to play]

Part C) Explain your answer in Part B: Why or Why not?

Explanation / Answer

A) frequency is inversely proportional to length

so 440/587 = L/60

L = 44.974 cm

B) No, its impossible to play

C) As for a frequency of 392 length oh string required = 440 x 60/392 = 67.347 cm which is more than the length of string i.e. 60 cm

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.