Wile E. Coyote, having missed the Road Runner, leaves the edge of a cliff at 37.

Question

Wile E. Coyote, having missed the Road Runner, leaves the edge of a cliff at 37.0 m/s horizontal velocity. If the canyon is 112 m deep, how far from the base of the cliff does the coyote land? 209.2 m 176.9m 174.9m 196.6m 207.0m 168.4m An object which is moving has a force in the direction of motion acting on it. (Definite/No Way/Maybe) Two forces are applied to an object as shown. using F_1 = 120_N phi_1 = 67 degreee, F_2 = 170_N and phi_2 = 17 degreee, find the net force on the object. magnitude 130.7_N 140.8_N 140.9_N 176.1_N 100.3_N 111.7_N direction 27.71 degreee 26.13 degreee 26.35 degreee 39.61 degreee 16.3 degreee 26.35 degreee

Explanation / Answer

given F1 = 120 @ 67 deg

F2 = 10 N @ 17 deg

F1x = Fx cos theta = -120 cos 67 = -46.88 N ( towards left on object)

F1y = 120 * sin 67 = 110.456 N upwards

F2x = 170 cos 17 = 162.57 N towards right

F2y = 170 sin 17 = - 49.70 downwards

Fx net = -46.88 + 162.57 = 115.69 N

Fy net = 110.456 - 49.70 = 60.75 N

Fnet^2 = Fx^2 + Fy^2

Fnet^2 = 115.69^2 + 60.75^2

Fnet = 130.7 N , Option A

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#12:

tan theta = Fy/Fx

tan theta = 60.75/115.69

tan theta = 0.525

theta = 27.71 deg, option A

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