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Abby throws a ball straight up and times it. She sees that the ball goes by the

ID: 1418421 • Letter: A

Question

Abby throws a ball straight up and times it. She sees that the ball goes by the top of a flagpole after 0.50 s and reaches the level of the top of the pole after a total elapsed time of 4.1 s. What was the speed of the ball at as it passed the top of the flagpole? Neglect air resistance.

6.4 m/s

16 m/s

18 m/s

29 m/s

33 m/s

A hammer is thrown upward with a speed of 14 m/s on the surface of planet X where the acceleration due to gravity is 3.5 m/s2 and there is no atmosphere. What is the speed of the hammer after 8.0 s?

7.0 m/s

14 m/s

21 m/s

64 m/

The magnitude of the resultant of two vectors cannot be less than the magnitude of either of those two vectors.

True

False

A ball is thrown horizontally from the top of a tower at the same instant that a stone is dropped vertically. Which object is traveling faster when it hits the level ground below if neither of them experiences any air resistance?

It is impossible to tell because we do not know their masses.

the stone

the ball

Both are traveling at the same speed.

On a calm day with no wind, you can run a 1500-m race at a velocity of 4.0 m/s. If you run the same race on a day when you have a constant headwind that slows your speed by 2.0 m/s, how much time would it take you to finish the race?

250 s

750 s

1125 s

9000 s

A plane has an airspeed of 142 m/s. A 16 m/s wind is blowing southward at the same time as the plane is flying. If the velocity of the plane relative to the ground is directly eastward, what is the magnitude of that velocity?

130 m/s

16 m/s

160 m/s

141 m/s

48 m/s

6.4 m/s

16 m/s

18 m/s

29 m/s

33 m/s

Explanation / Answer

A hammer is thrown upward with a speed of 14 m/s on the surface of planet X where the acceleration due to gravity is 3.5 m/s2 and there is no atmosphere. What is the speed of the hammer after 8.0 s?

Vi = initial velocity = 14 m/s

a = acceleration = - 3.5

Vf = final velocity

t = time = 8 sec

using the equation

Vf = Vi + at

Vf = 14 + (-3.5) (8) = - 14 m/s

speed = 14 m/s

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