Person 1 MInbox aalduways@mail.u x MasteringPhysics: Scores x Mastering Physics:
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Person 1 MInbox aalduways@mail.u x MasteringPhysics: Scores x Mastering Physics: HW due X MCChegg study l Guided solu x C http 6423847 PHY 2049 Summer C: Calculus Based Physics 2 with Dr. Criss Signed in as abdulrahman alduways l Help Close HW due 6/20 Problem 25.64 Resources previous l 2 of 3 l next Problem 25.64 Part A A person with body resistance between his hands of 12 k2 accidentally grasps the If the internal resistance of the power supply is 2200 n, what is the current through the person's body? terminals of a 13-kV power supply. Express your answer using two significant figures. Submit My Answers Give Up Part B What is the power dissipated in his body? Express your answer using two significant figures. Submit My Answers Give Up Part C If the power supply is to be made safe by increasing its internal resistance, what should the internal resistance be for the maximum current in the above situation to be Imax 00 mA. or less? Express your answer using two significant figures. Submit My Answers Give Up Provide Feedback ContinueExplanation / Answer
Internal resistance of the power supply = r = 2200
Body resistance between hands = R = 12k =12000
Power supply voltage = E =13 kV=13000 V
The current through the person's body = i = E / (R+r)
The current through the person's body = i =13000 /14200
(a) The current through the person's body = i =0.915 A
_____________
(b) The power dissipated in his body =i^2R=10046.7 W
___________________________
If Imax = 1.00 mA =0.001A
R+r=E/Imax
r =E/Imax - R
r = 13000/0.001 - 12000
r =13000000 -12000=12988000
(c) The internal resistance should be12988000 ohm for the maximum current in the above situation to be I(max) = 1.00 mA or less
The internal resistance should be1.2988000*10^7 ohm or 12.988 mega ohm
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